Powering the LED from a 1.5 volt battery
LEDs have long supplanted incandescent bulbs from almost all areas. This is understandable: the LED is superior in brightness to the lamp, considering its power consumption. But there are also a number of disadvantages to LEDs. Of course we will not talk about everyone, but we will discuss one. This is a high threshold of the initial power supply - it is about 1.8-2.2 volts. Naturally, you cannot power it with one battery ... To eliminate this drawback, we will build a simple converter using the absolute minimum of parts. With this converter, you can connect an LED (or several LEDs) to one battery and make a small flashlight. We need:This is the simplest blocking generator, with a free frequency of excitation. The idea is as old as the world. The device will have a high efficiency.
- 2N3904 or silicon transistor BC547, or any other npn structure.
- 1 kΩ resistor.
- Ring-shaped or ferrite hearts.
Converter circuitI will give you two circuits.One for winding a ring transformer, the other for those who don’t have a ring core at hand.
Winding inductorRegardless of whether you are using a ring core or a regular ferrite core, wind 10 turns of each winding. Your inductor is ready for this.
Generator checkAssemble according to a circuit and check. The generator should work and does not need adjustment. If suddenly the LED does not light up when the elements are intact, try changing the ends of one of the windings of the induction transformer. Now, the LED shines very brightly even from a dead battery. The bottom edge of the power supply of the entire device is somewhere around 0.6 volts. The efficiency of a transformer on a ring core is slightly larger.Not critical of course, but just keep in mind.
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